Iam so so glad that i didnt made 1 Penny in freebitcoin as the fork solution made just admin richer
Topic: FreeBitco.in-$200 FreeBTC🏎Win Lambo🔥0.2BTC DailyJackpot🏆$32,500 Wager Contest - page 268. (Read 405405 times)
November 26, 2017, 06:57:59 AM
Iam so so glad that i didnt made 1 Penny in freebitcoin as the fork solution made just admin richer
November 26, 2017, 06:45:53 AM
Update
Iam so so glad that i didnt made 1 Penny in freebitcoin as the fork solution made just admin richer
November 26, 2017, 05:37:38 AM
This appears to be one of the best faucets around. I have tried to do a manual withdrawal a few times and noticed that the withdrawal fee ranges from 400 sat to XX,XXX sat depending on what time I try to withdraw. 400 sat to almost 10,000 sat is a large variation in the fees.
the fee is based on the amount of unconfirmed transactions on the network
November 26, 2017, 05:32:50 AM
This appears to be one of the best faucets around. I have tried to do a manual withdrawal a few times and noticed that the withdrawal fee ranges from 400 sat to XX,XXX sat depending on what time I try to withdraw. 400 sat to almost 10,000 sat is a large variation in the fees.
November 25, 2017, 06:04:20 PM
Update
November 25, 2017, 04:50:28 PM
^ it's probably accurate, specially the part about btc price going up and free base roll reward going down.
Also I'd like to point out that even if my deposits are more than double the free roll winnings, I still got the captcha.
Also I'd like to point out that even if my deposits are more than double the free roll winnings, I still got the captcha.
November 25, 2017, 03:33:35 PM
When I started on freebitco.in about 2 months ago, I bought lottery tickets in batches of 500 to see how much percentage the FREE BTC rewards went up by, and worked out I would need to drop about 25k satoshi in to lottery tickets to hit the next level. So I saved everything until I reached 25k satoshi. Tested it again with batches of 500 - now it looks like I would need around 40k satoshi to hit the next level.
With the amount of satoshi per roll forever going down (as bitcoin price is forever going up), it seems like it will be impossible to reach the next level and stay there without external deposits.
Is this accurate or have I missed something?
With the amount of satoshi per roll forever going down (as bitcoin price is forever going up), it seems like it will be impossible to reach the next level and stay there without external deposits.
Is this accurate or have I missed something?
November 25, 2017, 10:04:13 AM
X.XX% achieved towards the next BTC bonus!
whats going on with this % number?
mine just decline , while im buyin tickets & playing multiply
whats going on with this % number?
mine just decline , while im buyin tickets & playing multiply
November 25, 2017, 06:07:41 AM
Hello! Wanted to ask about whether the site will react to fork with BT diamond (BTD)?
Diamonds isnt officialy annouced to be done... At least i has found only couple unconfirmed news about it...
November 25, 2017, 05:30:00 AM
Great balls of fire! We're rollin in the deep on an EPIC Rewards Points bonus weekend >>>>> 5x Rewards Points starts tonight!
For the entire weekend, we'll pay you 10 Rewards Points for a free roll, 5 Rewards Points for a multiply roll activity exceeding 1500 satoshi, and 5 Rewards Points for a referral roll!
Who's coming with me?
Follow us on Twitter to get more announcements of great promotions > https://twitter.com/freebitco
For the entire weekend, we'll pay you 10 Rewards Points for a free roll, 5 Rewards Points for a multiply roll activity exceeding 1500 satoshi, and 5 Rewards Points for a referral roll!
Who's coming with me?
Follow us on Twitter to get more announcements of great promotions > https://twitter.com/freebitco
Great news! By the way, will freebitco support Bitcoin Diamond fork?
November 25, 2017, 02:04:10 AM
Great balls of fire! We're rollin in the deep on an EPIC Rewards Points bonus weekend >>>>> 5x Rewards Points starts tonight!
For the entire weekend, we'll pay you 10 Rewards Points for a free roll, 5 Rewards Points for a multiply roll activity exceeding 1500 satoshi, and 5 Rewards Points for a referral roll!
Who's coming with me?
Follow us on Twitter to get more announcements of great promotions > https://twitter.com/freebitco
For the entire weekend, we'll pay you 10 Rewards Points for a free roll, 5 Rewards Points for a multiply roll activity exceeding 1500 satoshi, and 5 Rewards Points for a referral roll!
Who's coming with me?
Follow us on Twitter to get more announcements of great promotions > https://twitter.com/freebitco
November 24, 2017, 08:43:18 PM
I still have IP block, not using VPN or Proxy but still blocked, send MP, message at FAQ and nothing, not even I "I'll check"...
November 24, 2017, 02:53:33 AM
Hello! Wanted to ask about whether the site will react to fork with BT diamond (BTD)?
November 24, 2017, 02:52:45 AM
-snip-
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
What is this?
It's how you calculate the chance of winning $200 of Bitcoin on a free roll. As it says in its conclusion "WIN CHANCE is 0.005000 % per each roll."
This makes it a 1 in 20,000 chance rather than a 1 in 10,000 chance that many assume. This is due to rounding to the nearest whole number so you need to roll above 9999.5 to win.
November 24, 2017, 01:35:44 AM
-snip-
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
What is this?
November 24, 2017, 01:05:39 AM
//**********************************************
// Online C++ Compiler.
// https://www.onlinegdb.com/online_c++_compiler
//**********************************************
#include
#include
using namespace std;
int main()
{
unsigned int MagicNumber, RolledNumber;
double dTemp;
MagicNumber = 4294752547;
printf("\n Rounding Decimals to the Nearest Whole Number.");
// #0
dTemp = (double) (MagicNumber - 1) / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber - 1 = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber - 1, dTemp, RolledNumber);
// #1 (success)
dTemp = (double) MagicNumber / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber, dTemp, RolledNumber);
// 2^32 = 4294967295 + 1, 4294967295 - 4294752547 + 1 = 214749.
printf("\n Conclusion. There are only 214749 numbers for which a rolled number will be 10000.");
printf("\n The first suitable number is %lu.", MagicNumber);
printf("\n WIN CHANCE is %.06f %% per each roll.", 214749.0/4294967295.0 * 100.0);
return 0;
}
Output:
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
// Online C++ Compiler.
// https://www.onlinegdb.com/online_c++_compiler
//**********************************************
#include
#include
using namespace std;
int main()
{
unsigned int MagicNumber, RolledNumber;
double dTemp;
MagicNumber = 4294752547;
printf("\n Rounding Decimals to the Nearest Whole Number.");
// #0
dTemp = (double) (MagicNumber - 1) / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber - 1 = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber - 1, dTemp, RolledNumber);
// #1 (success)
dTemp = (double) MagicNumber / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber, dTemp, RolledNumber);
// 2^32 = 4294967295 + 1, 4294967295 - 4294752547 + 1 = 214749.
printf("\n Conclusion. There are only 214749 numbers for which a rolled number will be 10000.");
printf("\n The first suitable number is %lu.", MagicNumber);
printf("\n WIN CHANCE is %.06f %% per each roll.", 214749.0/4294967295.0 * 100.0);
return 0;
}
Output:
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
What is this?
November 23, 2017, 09:15:59 PM
Can we withdraw BTG? I want to hold BTG.
This is coming, hang in there...we're working on it as I type this post!
Cheers.
Yeah, thanks for your support.
November 23, 2017, 04:15:26 PM
//**********************************************
// Online C++ Compiler.
// https://www.onlinegdb.com/online_c++_compiler
//**********************************************
#include
#include
using namespace std;
int main()
{
unsigned int MagicNumber, RolledNumber;
double dTemp;
MagicNumber = 4294752547;
printf("\n Rounding Decimals to the Nearest Whole Number.");
// #0
dTemp = (double) (MagicNumber - 1) / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber - 1 = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber - 1, dTemp, RolledNumber);
// #1 (success)
dTemp = (double) MagicNumber / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber, dTemp, RolledNumber);
// 2^32 = 4294967295 + 1, 4294967295 - 4294752547 + 1 = 214749.
printf("\n Conclusion. There are only 214749 numbers for which a rolled number will be 10000.");
printf("\n The first suitable number is %lu.", MagicNumber);
printf("\n WIN CHANCE is %.06f %% per each roll.", 214749.0/4294967296.0 * 100.0);
return 0;
}
Output:
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
// Online C++ Compiler.
// https://www.onlinegdb.com/online_c++_compiler
//**********************************************
#include
#include
using namespace std;
int main()
{
unsigned int MagicNumber, RolledNumber;
double dTemp;
MagicNumber = 4294752547;
printf("\n Rounding Decimals to the Nearest Whole Number.");
// #0
dTemp = (double) (MagicNumber - 1) / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber - 1 = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber - 1, dTemp, RolledNumber);
// #1 (success)
dTemp = (double) MagicNumber / 429496.7295;
RolledNumber = (unsigned int)round(dTemp);
printf("\n MagicNumber = %lu, dTemp = %.08f, RolledNumber = %lu.", MagicNumber, dTemp, RolledNumber);
// 2^32 = 4294967295 + 1, 4294967295 - 4294752547 + 1 = 214749.
printf("\n Conclusion. There are only 214749 numbers for which a rolled number will be 10000.");
printf("\n The first suitable number is %lu.", MagicNumber);
printf("\n WIN CHANCE is %.06f %% per each roll.", 214749.0/4294967296.0 * 100.0);
return 0;
}
Output:
Rounding Decimals to the Nearest Whole Number.
MagicNumber - 1 = 4294752546, dTemp = 9999.49999852, RolledNumber = 9999.
MagicNumber = 4294752547, dTemp = 9999.50000085, RolledNumber = 10000.
Conclusion. There are only 214749 numbers for which a rolled number will be 10000.
The first suitable number is 4294752547.
WIN CHANCE is 0.005000 % per each roll.
November 22, 2017, 12:54:51 PM
BTW, I can't see the option to exchange Bitcoin Gold.
Are you looking on the FreeBitco.in site? If so, did you have Bitcoin on balance with us prior to and including October 24th of this year?
November 22, 2017, 12:29:29 AM
BTW, I can't see the option to exchange Bitcoin Gold.
Are you looking on the FreeBitco.in site? If so, did you have Bitcoin on balance with us prior to and including October 24th of this year?
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