OK, believe what you will. I do know several "licensed" electricians and had one confirm with me today, after these exchanges, that it is Per Phase on the Main - not total.
So each phase can be loaded with 80% load and the main will not trip as they are out of phase and not an addition of current.
Here is a list of miners and wattage that I am currently using - all at 120V. They alone are exceeding 200A in power usage -
13 x s7's = 15730 WATTS
8 x s5's = 4720 WATTS
1 x S4 = 1400 WATTS
3 x A2 @ 88 = 2250 WATTS
4 x A2 @ 110 = 4000 WATTS
TOTAL WATTS = 28100 @ 120v = 234A
The only 240V circuits being used are 1) Stove - 2) Water Heater.
Even with the miner loads, I'm still able to use all sorts of other electricity - IE this computer - a couple 1000 Watt gaming machines, a 200 Watt Laser Cutter, air compressors, electric drills, radios, garbage disposal, hair dryers (when gf needs), and charge my Chevy Volt.
You are saying this is impossible, unless defective - seems to be working.
Don't forget. You know we have 200 amps on each pole but how many volts is on each pole? The answer: 120 Volts
Yes, exactly. So where do you think the 240V comes from? Combining the 120V across the 2 poles. Essentially when you use a 240V breaker and have a 5A load on it, you are pulling 5A across both pole/legs at 120V.
So in order to achieve 200 amps at 240V you'd be pulling 200amps across both legs of 120V. This alone, seems to tell me that yes you can use 200A of 120V on each leg.
Yes Stove/Oven, Water Heater, and Dryer (which I don't use) all utilize both legs with 2 pole breaker. Who needs a dryer with this many miners? Just put up some clothes racks in the living room when its time to dry.
Then do the math...
200 amps x 120 volts for one leg (pole) = 24,000 watts.
200 amps x 120 volts for the other leg (pole) = 24,000 watts.
That is a total of 48,000 watts.
You are using 32,000 watts worth of rigs, "supposedly" at 120 Volts.
That leaves 18,000 watts remaining.
30 amp x 240 for your dryer = 7,200 watts [Actually uses about 22 amps x 240 Volts while running on normal dry = 5,280 watts]
50 amp x 240 for your A/C = 12,000 watts [Your A/C would actually use about 42 amps for start up power then throttle down to about 22 amps x 240 volts = 5,280 watts]
30 amp x 240 for your stove top/oven [Will probably use about 15 amps on average when it is on = 3,600 watts]
Those 3 combined [While running] = 14,160 watts plus the 32,000 watts of rigs you are "supposedly" running = 46,160 watts. This leaves 1,840 watts remaining and we haven't even gotten to the fridge, televisions, lights, stereo, gaming equipment you discussed, the compressor you discussed. You said all of this worked fine without tripping the Main Breaker. Yet, I find that hard to believe.
How about providing photos of your set up and photos of the Main Service Panel? Photos of all the outlets the rigs are connected to? IF you don't know how to post photos, I'll explain it to you.
I've racked my brain trying to figure out how you would "balance" 32,000 watts at 120 Volts for a total of 266 amps with 134 amps remaining and still power everything else I mentioned.
Not only that, you said the MAIN breaker appears to be 180 amps in an earlier post instead of 200 amps. That's even worse...
Did you not see the drawing I posted earlier depicting two 120 volt poles with Phase - A and Phase - B?
I see now you say you don't ever cook, you don't use the dryer and you always take cold showers. [I'm commenting on your post while I read it.] I imagine you turn the A/C on during the summer. Then we have the fridge, the compressor you mentioned, the 1,000 watt gaming you do, the lights, the television(s), your exhaust fan for heat; any other box fans you may use for cooling, your dish washer, etc...
The only way possible you "might" be able to do it is by NEVER cooking and NEVER drying clothes while the AC is running. You gave the impression that you can do all of these things I mentioned earlier just fine and you are just now saying you don't cook, and you don't dry clothes. When you say you worked hours on paper to figure out how to "balance" so EVERYTHING would work fine, you seemed to have left out never cooking and never drying clothes.
It's nothing to be embarrassed about for sure. During the summer, I would turn off a couple of rigs while the A/C was running so I could run the dryer or cook. I imagine you would be grateful for the winter so the A/C can be shut off to allow you to take hot showers and dry clothes or cook if you want to.
I would cut off 4 rigs if I wanted to cook and use the dish washer. I would have to cut off 7 rigs if I wanted to cook on 3 eyes of the stove, wash dishes and run the dryer on low. Then I would turn all the rigs I had shut off back on when I was finished drying clothes, cooking and washing dishes.
When this discussion first started, you said, "
Everything worked fine without tripping the main breaker." That was a bit misleading after finding out [During the summer with the A/C running] you never cooked nor dried clothes in the dryer and appear to always take cold showers as well because you cut off an electric water heater as well during the summer when the A/C is running.
How about some photos?
You can post the photos here [At "Miner Photo Porn"] to avoid cluttering up this particular thread:
https://bitcointalk.org/index.php?topic=766998.940By the way, I'm normally accustomed to saying 120 Volts and 240 Volts instead of 110 Volts and 220 Volts like others may say. One reason why it can be different depends on the internal resistance of the meter one is using when measuring voltage. The meter I prefer to use when measuring AC voltage in the Main Panel, receptacles or house wiring has an internal resistance of 10 million ohms.
The internal resistance of any meter [When measuring voltage] is HIGH [Some higher than others]. Why should the internal resistance of a volt meter be high? We do NOT want current to flow. Why? So we can see the Source Voltage (potential output of our power supply). If the internal resistance of a volt meter was low, a substantial amount of current would flow through the meter and it would be impossible to see Source Voltage (120V or 240V) . If current was flowing through the meter, we would see what is called, "Voltage Drop" instead of Source Voltage.
That's why the internal resistance of a volt meter MUST be high. Why? To keep a substantial amount of current from flowing through the meter. Why? So our meter leads will extend to the Source. Why? So, we can see the potential output of our power supply, known as "Source Voltage" (120V or 240V).
If we see SOME voltage [Meaning it's not zero volts, but 40 Volts for example] However, that 40 volts is not source voltage (120 Volt or 240 Volt), the 40 volts we are seeing is more than likely voltage drop. Which means current is flowing. More than likely a hot wire (conductor) has access to ground [When working on AC Volts] OR the negative and positive side of the battery has contact somehow [When working on DC Volts].
[It is possible to have a partial open in the cable or wire extremely high in resistance that can affect your voltage reading so much to make you think you are seeing voltage drop to indicate current is flowing. However, an open of any type does not create leakage. Meaning, an open does not get current to flow.] I will say it is highly unlikely a partial open has that high of resistance to knock your voltage down to a point that fools you into believing you are seeing voltage drop. It would normally be clean open by the time a technician arrives. Which would result in no voltage seen at all; depending on the conductor that is open and the points measured with the meter leads. If current is ever flowing through resistance in a conductor, that conductor will drop (consume; eat) voltage. So, if we see SOME voltage but not SOURCE voltage, it more than likely is voltage drop, which means current is flowing.
If we have concluded current is flowing because of seeing voltage drop, the type of troubles that can create this would be a short, ground or cross of some kind [Depending of whether it is AC or DC of course].Some meters have an internal resistance of 1,000,000 Ohms [When measuring voltage] and would give us a 110 Volts or 220 Volts AC reading. While other digital meters may have an internal resistance of 10,000,000 Ohms [When measuring voltage] and give a reading of 120 volts or 240 Volts AC. I have digital and analog meters with both 1Meg. Ohms and 10 Meg. Ohms internal resistance when measuring AC or DC voltage.
Cheers,